Solution:
In the end: Z = L à 174
After L gave 2/5, she had 3 units left.
So 3u à 174
1u à 58
Z received 2u from L, so Z originally had 174 – 2u à 174 – 116 = 58
Before L gave 2/5, she had 5 units. 5u à 290
Z had 58 after he gave 1/3, 2u à 58, 1u à 29 (given to L)
L had 290 after she received 29
L at first à 290 – 29 = 261
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